A.5 Infinite Plate to Any Area on Parallel Plate

In Fig. A-5 consider on one plate an element dAk, and on the other plate a concentric ring element dAj centered about the normal to dAk. The geometry is like that in Fig. A-2 for a ring on the top of a cylinder to the center of its base. Then, from (A-6),

 

 

where kλD is the optical spacing between the plates. By using the procedure leading to (A-8), the integral is transformed to . Then integrating over any finite area Ak as in Fig. A-5 gives . With  and Fk–j = 1, this reduces to

 

                                                         (A-13)

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FIGURE A-5 Isothermal layer of medium between infinite parallel plates.